Question 1201406
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There are infinitely many points on this line since there are infinitely many numbers we could replace x with (or we could replace y with).


Let's say we plugged in x = 0.
Solve for y.
6y+3x = 5
6y+3(0) = 5
6y = 5
y = 5/6
When x = 0, it leads to y = 5/6
One point on this line is (0, 5/6) which is the y-intercept.
The y-intercept is where the line crosses the y axis.


Now let's plug in y = 0 and solve for x.
6y+3x = 5
6(0)+3x = 5
3x = 5
x = 5/3
The x-intercept is located at (5/3,0)
The x-intercept is where the line crosses the x axis.


Graph
{{{
drawing(400,400,-3,3,-3,3,
graph(400,400,-3,3,-3,3,-100,(5-3x)/6),
circle(5/3,0,0.04),
circle(5/3,0,0.06),
circle(5/3,0,0.08),
circle(5/3,0,0.10),

circle(0,5/6,0.04),
circle(0,5/6,0.06),
circle(0,5/6,0.08),
circle(0,5/6,0.10),

locate(0.25,5/6+0.2,"(0,5/6)"),
locate(5/3,0.4,"(5/3,0)")

)
}}}
Desmos and GeoGebra are two graphing options I recommend.
5/6 = 0.8333 approximately
5/3 = 1.6667 approximately


There isn't a rule you have to use zero. It just happens to be the easiest value to work with. 
Feel free to try other values such as x = 1 or y = 5.
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