<PRE><B>Question 1201362</B>
.
(1) Ali had 60% of the total number of marbles his other 3 friends had. 
(2) Cindy had 50% of the total number Ben and Daniel had. 
(3) The number Ben had was 1/3 the number daniel had. 
(4) If ali had 39 more marbles than daniel, how many did they have altogether. 
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&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;For convenience of referencing, &amp;nbsp;I numbered the statements &amp;nbsp;(1), &amp;nbsp;(2), &amp;nbsp;(3) &amp;nbsp;and &amp;nbsp;(4).



&lt;pre&gt;
Let x be the number of marbles Ben had.


Then from (3), Daniel had 3x marbles,
     and Ben and Daniel had together x+3x = 4x marbles.


Then from (2), Cindy had 0.5*(4x) = 2x marbles, 
     and 3 friends, Ben, Cindy and Daniel, had together 4x+2x = 6x marbles.


Then from (1), Ali had 0.6*(6x) = 3.6x marbles.


We are given in (4), that 

    3.6x - 3x = 39.


It gives us

    0.6x = 39,  x = {{{39/0.6}}} = 65.


Hence, altogether they had  6x+3.6x = 9.6x = 9.6*65 = 624 marbles.    &lt;U&gt;ANSWER&lt;/U&gt;
&lt;/pre&gt;

Solved using one unknown and one equation.



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