Question 1201235
let b = the number of sweets that bob had.
let j = the number of sweets that jill had.


After Jill gave Bob 20% of what she had, Bob would have 60% more than Jill. 


assume jill had x number of sweets.
after she gave 20% of them to bob, she would have had .8x number of sweets left.


after jill gave 20% of her sweets to bob, bob would have had 1.6 * the number of sweets that jill had left.


bob would have had 1.6 * .8 * x = 1.28 * x sweets.


after the transaction:
bob had 1.28 * x number of sweets.
jill had .8 * x number of sweets.


you want to know what percentage of sweets that bob had were given to jill so that they both have the same number of sweets.


let that quantity be equal to y.


you get 1.28 * x - y = .8 * x + y
add y to both sides of this equation and subtract .8 * x from both sides of this equation to get:
1.28 * x - .8 * x = 2 * y
simplify to get:
.48 * x = 2 * y
solve for y to get:
y = .48 / 2 = .24 * x


replace y with .24 * x in the equation of 1.28 * x - y = .8 * x + y.
the equation becomes:
1.28 * x - .24 * x = .8 * x + .24 * x
simplify to get:
1.04 * x = 1.04 * x


the ratio of .24 * x to 1.28 * x is equal to (.24 * x) / (1.28 * x) = .1875.
this suggest that bob would have had to give 18.75% of what he had to jill so that they would both have the same amount.


to see if this makes sense, let x = any random number that makes some kind of sense.
i let x = 1000


that's the amount that jill had to start with.
she gave 20% of that to bob
bob would then have had 1.6 * what jill had left.
jill would have had 800 left.
bob would have had 1280, because 1.6 * 800 = 1280.


bob would then have had to give 18.75% of that to jill so that they would both have the same amount.
.1875 * 1280 = 240.
bob gave 240 to jill.
bob now has 1280 - 240 = 1040.
jill now has 800 + 240 = 1040.
they both now have the same amount.


it looks like your solution is that bob would have had to give 18.75% of his sweets to jill so that they would both have the same number of sweets.