Question 1201222
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A binomial experiment with the number of trials n=5;  
                           the probability of success of an individual trial p= 0.5;
                           the number of success trials k=3.


Use the standard formula

    P = {{{C[5]^3*p^k*(1-p)^(5-k)}}} = {{{((5*4)/(1*2))*0.5^3*0.5^2}}} = {{{10/2^5}}} = {{{10/32}}} = 0.3125.    <U>ANSWER</U>
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Solved.