Question 1201169


sin2x/cos x = 2,

sin 2x = 2 sinx.cosx

2sinx.cosx/cosx = 2

2sinx = 2
sin x =1
x=pi/2

But in the equation
sin2x/cos x = 2,

If x = pi/2 , cos(pi/2) =0 

sin2x/0
So equation is indeterminate