Question 1201141


 *[illustration PENTAGON.png].

All sides of pentagon equal
Interior angles of polygon =108 deg

AB=BC in triangle ABC  Isoscles triangle
AE =ED in triangle AED Isoscles triangle

Sum of anglesof triangle =180 deg

36+36+108=180 deg

Angle BAE = 108
Therefore angle CAD =36  deg

Angle BAD = angle ADE

But they are alternate angles forme by transversal AD
Therefore AC || DE