Question 1201138
The six consecutive odd integers
{{{system(n-5,n-3,n-1,n+1,n+3,n+5)}}}


Sum
{{{(n-5)+(n-3)+(n-1)+(n+1)+(n+3)+(n+5)}}}
.
.
{{{6n}}}


That sum is 468.
{{{6n=468}}}

{{{n=468/6}}}

{{{n=78}}}--------------


The smallest of the asked-for integers,
{{{n-5}}}
{{{78-5}}}
{{{highlight(73)}}}