Question 1200944
*[illustration LP.png].
Let number of units of A be x and that of B be y

Raw Material
Product A Raw material = 2kg
Product B raw material =3kg
Available Raw material 60 kg per week

Labour 
Product A  4hours 
Product B 3 hours
Total hours avaiable = 96

We can formulate two equations as follows
{{{2x+3y <= 60}}}     When x = 0, y=20 (0,20) When y=0, x=30 (30,0)
{{{4x+3y <= 96}}}     When x=0 y=32 (0,32)   when y=0 x=24    (24,0) 
Profit be z
z=40x+35y
The feasible area is the shaded portion.
The points are O (0,0) C(24,0), P(18,8) ,D (0,32)
z=40x+35y
At O z=0
At C , 24*40+35*0 =960
At P 40*18+35*8= 1000
At D 40*0 +32*35= 700
At P(18,8) we get maximum output 
18 units of A and 8 units of B