<PRE><B>Question 1201092</B>
.



&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;In this post, &amp;nbsp;I will answer question &amp;nbsp;(i), &amp;nbsp;only.



&lt;pre&gt;
(i)  to calculate the mean and the standard deviations for the binomial distribution, use the formulas

    mean = np = 1000*0.10 = 100.    &lt;U&gt;ANSWER&lt;/U&gt;


    SD = {{{sqrt(n*p*(1-p))}}} = {{{sqrt(1000*0.1*(1-0.1))}}} = {{{sqrt(90)}}} = 9.4868 (rounded).     &lt;U&gt;ANSWER&lt;/U&gt;
&lt;/pre&gt;

Solved.



</PRE>