Question 1201106
*[illustration aerial.png].



AB =9.6 m

{{{(alpha)}}} = 12 deg. {{{(beta) = (90-(alpha))}}}

90-12 = 78

Law of cosines

AC^2  =AB^2+BC^2 −2(AB)(BC)cos∠ABC
 = (9.6)^2 + (10)^2 - 2*(10)*(9.6)*cos (78deg)
=152.24 m
length of the stay = 152.24 m

Law of sines 
(sin∠ACB/AB ) = (sin∠ABC/AC)

Find the angle


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