Question 114803
{{{y=log(b,x)}}} => {{{x=b^y}}}


Since you did not specify the base (b in the above), I'm going to assume base 10 according to the convention that log implies base 10, ln implies base e, and anything else has to be specified.


So, {{{log((4x+1))=1}}} => {{{(4x+1)=10^1}}}


{{{4x+1 = 10}}}
{{{4x=9}}}
{{{x=9/4}}}


For the general base, b, the answer would be:


{{{x=(b-1)/4}}}