Question 1201065
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Refer to this diagram
{{{
drawing(600, 200, -4,4,-5,5,

red(line(-3,2.8,0,2.8)),
red(locate(-1.5, 3.7, "A=2")),
red(line(-3,3.3,-3,2.3)),
red(line(0,3.3,0,2.3)),

blue(line(-3,1,3,1)),
blue(locate(0.4,1.9, "B=4.9")),
blue(line(-3,1.5,-3,0.5)),
blue(line(3,1.5,3,0.5)),

line(-3-3,0,3+3,0),
line(-3,0.2,-3,-0.2),
line(0,0.2,0,-0.2),
line(3,0.2,3,-0.2),
locate(-3.2,-0.2,"0.1"),
locate(-0.2,-0.2,"2.1"),
locate(3,-0.2,"5"),

locate(-3.8,-3.3,matrix(1,2,Diagram,not)),
locate(-3.8,-4,matrix(1,2,to,scale))
)
}}}

The red segment (A) spans from 0.1 to 2.1
Its length is 2.1-0.1 = 2 units


The blue segment (B) goes from 0.1 to 5
length of B = 5-0.1 = 4.9


The chances of landing in region A is 
A/B = 2/4.9
A/B = 0.40816326530612
A/B = 0.40816
This approximately is about a 40.816% chance of happening.
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