Question 1201048
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x = amount invested in the 1st account
y = amount invested in the 2nd account


x+y = 23000 total invested
That can be solved to y = 23000-x
I'll use it in a substitution step later on.


10% of x = 0.10x = gains from the 1st account
-3% of y = -0.03y = loss from the 2nd account
0.10x-0.03y = -235 net loss


0.10x-0.03y = -235
0.10x-0.03( y ) = -235
0.10x-0.03( 23000-x ) = -235 .... substitution step
0.10x-0.03( 23000 ) - 0.03(-x) = -235
0.10x-690 +0.03x = -235
0.13x-690 = -235
0.13x = -235+690
0.13x = 455
x = 455/0.13
x = 3500


Use this to find y
y = 23000-x
y = 23000-3500
y = 19500


He invested $3500 in the first account and gained 0.10*3500 = 350 dollars.
He also invested $19,500 in the second account and lost 0.03*19500 = 585 dollars.
The net loss is 350-585 = -235 which matches what the instructions mentioned.
The answers are confirmed.



Answers:
<font color=red>$3500</font> invested in the first account.
<font color=red>$19,500</font> invested in the second account.
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