Question 1200982
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There are 3 red, 1 blue and 2 green marbles in a bag. 
A marble is randomly drawn from the bag twice, with replacement. 
What is the theoretical probability of choosing one red marble and one green marble?
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<pre>
  P(one red marble and one green marble) = 


  = P(1st marble is red; 2nd marble is green) + P(1st marble is green; 2nd marble is red) = 


  = {{{(3/6)*(2/6)}}} + {{{(2/6)*(3/6)}}} = {{{(1/2)*(1/3)}}} + {{{(1/3)*(1/2)}}} = {{{1/6}}} + {{{1/6}}} = {{{2/6}}} = {{{1/3}}}.   <U>ANSWER</U>
</pre>

Solved.