Question 1200974
<br>
The algebra for solving a problem like this is almost always easier if you take the time to analyze the given information so that you can set up the problem using a single variable.<br>
The number given to B is the smallest, so<br>
let x = number given to B
then 2x = number given to A (twice as many as B)
and 3x = number given to C (1 1/2 times as many as A)<br>
The total is 102:<br>
{{{x+2x+3x=102}}}
{{{6x=102}}}
{{{x=102/6=17}}}<br>
ANSWERS:
A: 2x = 34
B: x = 17
C: 3x = 51<br>