Question 1200878
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A school is sponsoring a fundraiser by selling athletic calendars. The total cost of printing the calendar 
is $440 plus an additional charge of $2.75 per calendar. How many calendars must be sold to keep 
the cost of printing under $5 per calendar?
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<pre>
Obviously, it should be

    {{{440/x}}} < 5 - 2.75 = 2.25,

or

    x > {{{440/2.25}}} = 195.56...


Rounding to the closest greatest integer, you get the final inequality

    x >= 196  calendars.    <U>ANSWER</U>
</pre>

Solved.