Question 1200841
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Since 3, 5, and 7 are relatively prime, any number divisible by 3, 5, and 7 is divisible by 3*5*7 = 105.<br>
Clearly the last digit must be 5; and a quick look at 375 and 735 shows that 735 is divisible by 105 while 375 is not. So<br>
ANSWER: 735<br>