Question 1200791
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Let *[tex \Large x] represent the amount of milk in each glass at the start.  Then the amount remaining in A is *[tex \Large x\ -\ 210]ml, and the amount remaining in B is *[tex \Large x\ -\ 150]ml.


The ratio of the two remaining amounts is then:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{x\,-\,210}{x\,-\,150}]


Which is given to be equal to *[tex \Large \frac{3}{8}], hence


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{x\,-\,210}{x\,-\,150}\ =\ \frac{3}{8}]


Solve for *[tex \Large x].


Hint: Cross-products are equal in any proportion.


Don't forget to specify your answer as some number of milliliters (ml).

																
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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