Question 1200749
<pre>
{{{y =  (3y^2)/(1-3xy)}}}

Multiply both sides by (1-3xy)

{{{y(1-3xy)=3y^2}}}

Divide both sides by y

{{{1-3xy=3y}}}

Add 3xy to both sides

{{{1=3y+3xy}}}

Factor out 3y on the right side

{{{1=3y(1+x)}}}

Divide both side by 3(1+x)

{{{1/(3(1+x))=y}}}

{{{expr(1/3)(1+x)^(-1)=y}}}

{{{-expr(1/3)(1+x)^(-2)(1)=dy/(dx)}}}

{{{-(1^"")/(3(1+x)^2)=dy/dx}}}

Edwin</pre>