<PRE><B>Question 1200711</B>
&lt;br&gt;
Ignore the solution from the other tutor; his process is faulty and his answer is wrong.&lt;br&gt;
{{{2x^2&lt;9x+18}}}&lt;br&gt;
It&#39;s a quadratic inequality.  Just as with a quadratic equation, move terms to get &quot;0&quot; on one side:&lt;br&gt;
{{{2x^2-9x-18&lt;0}}}&lt;br&gt;
Factor the quadratic:&lt;br&gt;
{{{(x-6)(2x+3)&lt;0}}}&lt;br&gt;
The value of the expression is 0 only at x=-3/2 and x=6; the sign of the evaluated expression can only change at those two values of x.  So there are three intervals we need to check to see on which of them the inequality is satisfied: (-infinity,-3/2), (-3/2,6), and (6,infinity).&lt;br&gt;
One standard way to do this is to choose a test value in each interval.  I leave it to you to do that if you want.&lt;br&gt;
Another easier way to determine the intervals on which the inequality is satisfied is to know that the graph of the quadratic is an upward-opening parabola; since the inequality is for the expression value to be negative, the solution set is the interval between the two zeros: (-3/2,6).&lt;br&gt;
ANSWER: (-3/2,6)&lt;br&gt;
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