Question 1200594
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Jim is three times as old as his son. In 10 years, Jim will be twice as old as his
son. What are their current ages?
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<pre>
The son's age = x years.

The Jim's age= 3x years.


In 10 years

    2(x+10) = 3x+10


Simplify and find x

    2x + 20 = 3x + 10

    20 - 10 = 3x - 2x

      10    =    x.


<U>ANSWER</U>.  The son is 10 years old.  Jim is 3*10 = 30 years old.
</pre>

Solved.


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For introductory age problems, &nbsp;look into the lessons

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=http://www.algebra.com/algebra/homework/word/age/Age-problems-and-their-solutions.lesson>Age problems and their solutions</A>

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/word/age/02-HOW-TO-algebreze-and-solve-age-problems.lesson>HOW TO algebreze and to solve age problems?</A> 

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=http://www.algebra.com/algebra/homework/word/age/Fresh-formulation-of-a-traditional-age-problem.lesson>A fresh formulation of a traditional age problem</A>

in this site.


Learn the subject from there.