Question 1200514
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There is one way to make a 2 or a 12
There are two ways to make a 3 or 11
There are three ways to make a 4 or 10
There are five ways to make a 5 or 8
There are four ways to make a 6 or 9
There are six ways to make a 7


There are a total of 36 possibilities.  15 (1 + 2 + 3 + 4 + 5) of these possibilities are less than 7 and therefore, 21 ways are 7 or greater.


The probability that less than 7 is rolled is *[tex \Large \frac{15}{36}\ =\ \frac{5}{12}]


The probability that less than 7 IS NOT rolled is then one minus the probability that less than 7 IS rolled.  You can do your own arithmetic.

																
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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