Question 114659
I have tried everything and I just don't understand this problem.
Here is the problem 

{{{ log(6,36) }}} = {{{5x + 3}}}

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We use the definition of a logarithm:

which says this: 

The equation log<B>A = C 

is equivalent to this equation

B<sup>C</sup> = A

That means that your equation:

{{{log(6,36)}}} = {{{5x + 3}}}

is equivalent to and can be replaced by
the equation:

{{{6^(5x+3)}}} = {{{36}}}

Now since 6×6=36, we can write 36 as 6<sup>2<//sup>

{{{6^(5x+3)}}} = {{{6^2}}}

Now since the base 6 is positive and not equal to 1,
we can equate the exponents of 6 on both sides:

{{{5x+3}}} = {{{2}}}

{{{5x}}} = {{{2-3}}}

{{{5x}}} = {{{-1}}}

{{{x}}} = {{{-1/5}}}

Edwin</pre>