Question 1200489
A stone is thrown with a velocity of 8 ms^-1 into the air at an angle of 40° to the horizontal.
(Give your answer to 2 significant figures).
a) Calculate the vertical component of the velocity.
vert = 8*sin(40) m/sec
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b) State the value of the vertical component of the velocity when the stone reaches its highest point. Ignore air resistance.
Zero (0).
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c) Use your answers to a and b to calculate the time the stone takes to reach its highest point.
Using 9.8 m/sec/sec for gravity:
v = at  ---> t = v/a
t = 8*sin(40)/9.8 to apogee
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d)Calculate the horizontal component of the velocity.
horiz = 8*cos(40)
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e)Use your answers to c and d to find the horizontal distance travelled by the stone as it climbs to its highest point.
horiz = 8*cos(40)*2t meters