Question 1200496
Find d^2y/dx^2 for y=csc(x)
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y = 1/sin = sin^-1
y' = {{{-sin(x)^-2*cos(x)}}}
y'' = {{{-2*sin(x)^-3*cos(x) + (-sin(x)^-2*(-sin(x)))}}}
y'' = {{{-2cos(x)/(sin(x)^-3) + csc(x)}}}
y'' = {{{csc(x)*cot^2(x) + csc^2(x)}}}