Question 1200446
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Part (a)


I'll use the notation "mps" to mean "meters per second" aka "m/s".


acceleration = (finalVelocity - startingVelocity)/(change in time)
acceleration = (20 mps - 4 mps)/(100 s)
acceleration = (16 mps)/(100 s)
acceleration = (16/100) m/s^2
acceleration = 0.16 m/s^2
This value is exact.


Answer: <font color=red size=4>0.16 m/s^2</font>


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Part (b)


average velocity = (startingVelocity + finalVelocity)/2
average velocity = (4 mps + 20 mps)/2
average velocity = (24 mps)/2
average velocity = 12 mps
average velocity = 12 m/s



Answer: <font color=red size=4>12 m/s</font>


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Part (c)


distance = averageVelocity*time
distance = (12 m/s)*(100 s)
distance = 1200 m


Answer: <font color=red size=4>1200 meters</font>


Further Reading about Kinematic Equations
<a href = "https://www.physicsclassroom.com/class/1dkin/Lesson-6/Kinematic-Equations">https://www.physicsclassroom.com/class/1dkin/Lesson-6/Kinematic-Equations</a>
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