Question 1200416
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Was solved many years ago at this forum under this link


<A HREF=https://www.algebra.com/algebra/homework/Rate-of-work-word-problems/Rate-of-work-word-problems.faq.question.653878.html>https://www.algebra.com/algebra/homework/Rate-of-work-word-problems/Rate-of-work-word-problems.faq.question.653878.html</A>


https://www.algebra.com/algebra/homework/Rate-of-work-word-problems/Rate-of-work-word-problems.faq.question.653878.html



&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;Alternative to that algebraic solutions is THIS mental solution below:



<pre>
When they will complete the job, Andrew will complete  5/6  of the job, while Bailey will complete  1/6  of the job.


Thus Bailey makes 1/6 of the job in 9 days.

Hence, Bailey can make the entire job in  6*9 - 54 days working alone.


It implies that Andrew can complete the job in  54/5 = 10 {{{4/5}}}  days, working alone.
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