Question 1200402
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Use the two-point form of an equation of a straight line:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ -\ y_1\ =\ \frac{y_2\,-\,y_1}{x_2\,-\,x_1}(x\ -\ x_1)]


Then simplify so that *[tex \Large y] is by itself in the LHS.


Replace *[tex \Large y] with *[tex \Large f(x)]


																
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
*[illustration darwinfish.jpg]

From <https://www.algebra.com/cgi-bin/upload-illustration.mpl> 
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*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
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