Question 1200308
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If Qasim has 4 times as many quarters as nickels and they have a combined value 
of 735 cents, how many of each coin does he have?
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<pre>
Let x be the number of nickels. 
Then the number of quarters is 4x.


Write the total money equation

    25 *(4x) + 5x = 735 cents.

Simplify and find x

    100x + 5x = 735

        105x  = 735

           x  = 735/105 = 7.


<U>ANSWER</U>.  7 nickels and 7*4 = 28 quarters.
</pre>

Solved.


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It can be solved mentally &nbsp;(the same solution as above, &nbsp;only re-told in wording form).


<pre>
Group coins in the sets in a way that each group consists of 1 nickel and 4 quarters.

According to the problem, such grouping is possible.

Each group is worth  4*25 + 5 = 105 cents.

The number of group is  735/105 = 7.


It gives the answer above.
</pre>

Solved in two ways, &nbsp;for your better understanding.