Question 1200263
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Here is an alternative to the standard algebraic solution method shown by the other tutors.  For a particular similar problem, this alternative method might (or might not!) make the solution easier.<br>
The distances both directions are of course the same; and the ratio of the two speeds is 1:1.2, or 5:6.  That means the ratio of times at the two speeds was 6:5.<br>
The total time for the trip was 7 hours 20 minutes, or 440 minutes.  Dividing the 440 minutes in the ratio 6:5 gives 240 minutes for the flight at the lower speed from A to B and 200 minutes for the flight at the higher speed from B to A.<br>
The question asks for the speed on the flight from A to B, which was 1500 miles in 240 minutes, or 4 hours; the speed was 1500/4 = 375 mph.<br>
ANSWER: 375 mph<br>