Question 1200263
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A pilot flew a jet from City A to City B, a distance of 1500 mi. 
On the return trip, the average speed was 20% faster than the outbound speed. 
The round-trip took 7 h 20 min. What was the speed from City A to City B?
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<pre>
Let x be the speed from A to B, in miles per hour.

Then the speed from B to A is 1.2 x, according to the problem.


The flight time from A to B is {{{1500/x}}}  hours.

The flight time from B to A is {{{1500/(1.2x)}}} = {{{1250/x}}} hours.


Total flight time for the round trip is  {{{1500/x}}} + {{{1250/x}}} = {{{2750/x}}}.


We are given that

    {{{2750/x}}} = 7{{{1/3}}} hours = {{{22/3}}} hours.


It gives us x = {{{2750/((22/3))}}} = {{{(2750*3)/22}}} = 375.


<U>ANSWER</U>.  The speed from A to B was 375 miles per hour.
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Solved.