Question 1200245
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You roll a fair six-sided die twice. Find the probability of rolling a 3 the first time 
and a number greater than 1 the second time.
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<pre>
Two events are independent; so

    P(both) = P(first)*P(second) = {{{(1/6)*(5/6)}}} = {{{5/36}}}.    <U>ANSWER</U>
</pre>

Solved.