Question 1200237
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This is one way to write out the data table.
<table border = "1" cellpadding = "5">
<tr><td></td><td>Age 18-21</td><td>Age 22-29</td><td>Total</td></tr>
<tr><td>Responds</td><td>65</td><td>263</td><td>328</td></tr>
<tr><td>Refuse to Respond</td><td>11</td><td>33</td><td>44</td></tr>
<tr><td>Total</td><td>76</td><td>296</td><td>372</td></tr>
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Define these events:
A = person is in the 18-21 age bracket
B = person responds


n(A) = number of people in the 18-21 age bracket
n(A) = 76
n(B) = 328
n(A and B) = 65
These values are found in the table above.


Use those values to compute the following.
n(A or B) = n(A) + n(B) - n(A and B)
n(A or B) = 76 + 328 - 65
n(A or B) = 339
There are 339 individuals who are either in the 18-21 age bracket, have responded, or both.


P(A or B) = n(A or B)/n(total)
P(A or B) = 339/372
P(A or B) = 0.911290322580645 approximately
P(A or B) = 0.911
P(A or B) = 91.1%



Answer: <font color=red size=4>91.1%</font>
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