Question 1200168
<pre>

The Pythagorean triple formula is 

{{{(matrix(1,5, m^2-n^2, ",",  2mn, ",", m^2+n^2))}}}, m > n

I will arbitrarily choose m = 11 and n = 8

{{{(matrix(1,5, 11^2-8^2, ",",  2*11*8, ",", 11^2+8^2))}}}

{{{(matrix(1,5, 121-64, ",",  176, ",", 121+64))}}}

{{{(matrix(1,5, 57, ",",  176, ",", 185))}}}

Proof that it's a Pythagorean triple:

{{{57^2+176^2 = 3249+30976 = 34225 = 185^2}}}

Now substitute m = 8 and n = 3

Edwin</pre>