Question 1200052
<pre>
MATERIALS       CONC.%     VOLUME       PURE
Pure Acid       100         v           100v
Lower Conc.      25         500         (25)(500)
ResultingMix     50        v+500        (50)(v+500)
</pre>
The amount of pure acid in the parts to be mixed is the same as the pure acid of the resulting mixing.


{{{100v+(25)(500)=50(v+500)}}}

-

{{{100v=50v+(50)(500)-(25)(500)}}}

{{{100v-50v=500*50-500*25}}}

{{{(100-50)v=500(50-25)}}}

{{{highlight_green(v=500((50-25)/(100-50)))}}}----------simplify and compute.