Question 1199999
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The given information that the number divided by 3 leaves remainder 1 is superfluous, because 9 is a multiple of 3 and the remainder when divided by 9 is 4.<br>
So the simplified problem is to find a number that leaves remainder 4 when divided by either 5 or 9.  But if the remainder is 4 when divided by either 5 or 9, then the remainder is 4 when divided by 5*9=45.<br>
So the given number could be any number that is 4 more than a multiple of 45.<br>
One simple obvious such number is 4+45 = 49.<br>
But other possibilities are 4+2(45) = 94, or 4+10(45) = 454, or even 4+(-3)(45) = -131.<br>
ANSWER (the PROBABLE expected one): 49<br>