Question 1199999
given:

a number, 

when divided by {{{ 9}}} the remainder is {{{ 4}}}
when divided by {{{ 5}}} the remainder is {{{ 4}}}
when divided by {{{ 3}}} the remainder is {{{ 1}}}

first find multiples 


Series one: multiples of {{{9}}} plus {{{4}}} -> {{{ 14}}}, {{{22}}}, {{{31}}}, {{{40}}},{{{49}}},{{{58}}},..........

Series two: multiple of {{{5}}} plus {{{4}}} ->  {{{9}}}, {{{14}}}, {{{19}}}, {{{24}}}, {{{29}}}, {{{34}}},{{{39}}},{{{44}}},{{{49}}},.................

Series three: multiple of {{{3}}} plus {{{1}}} ->{{{ 4}}}, {{{7}}}, {{{10}}}, {{{13}}}, {{{16}}}, {{{19}}},{{{ 22}}},{{{25}}},{{{28}}}.{{{31}}},{{{34}}},{{{37}}},{{{40}}},{{{43}}},{{{46}}},{{{49}}},...

first common: {{{49}}}


answer: the least number is {{{49}}}


or, simply

{{{LSD(9,5)=45}}}
{{{LSD(9,3)=9}}}

so, use

{{{N=LSD(9,5)+reminder=45+4=49}}}

The least number is {{{49}}}