Question 1199929
The above equation can be re written as 

{{{3x^4-x^3*y = 9317}}}

then we can factor out an {{{x^3}}} term

{{{x^3(3x-y) = 9317}}}

then we can prime factorize 9317, which gives us {{{7 * 11^3}}}

which means that from our above factored equation, x can be either 1 or 11

if x = 1

{{{3x - y = 7}}}
{{{-y = 4}}}
{{{y = -4}}} 

since we get a negative value of y, x can only be 11

{{{ 3(11) - y = 7}}}
{{{-y = -26}}}
{{{y = 26}}}

therefore the product of x and y is 286

cheers