Question 114630
Let x be the first (lower) number, then (x+1) is the next consecutive number.
{{{x(x+1) = 1056}}} The product of theses two numbers is 1056. Subtract 1056 from both sides.
{{{x^2+x-1056 = 0}}} Solve by factoring.
{{{(x-32)(x+33) = 0}}} Apply the zero product principle.
If {{{x-32 = 0}}} then {{{x = 32}}}
or
If {{{x+33 = 0}}} then {{{x = -33}}} Since the problem says "two consecutive natural numbers", discard the negtive solution.

{{{x = 32}}} and {{{x+1 = 33}}} These are the two numbers.

Check:
{{{32*33 = 1056}}}