Question 1199752
 How many mL's of a 10% alcohol solution and how many mL's of a 20% solution must be mixed to obtain 30 mL's of a 16% solution? 
:
let x = amt of 20% solution
total is be 30 ml, therefore
(30-x) = amt of 10%
:
Solve this simple mixture equation
.10(30-x) + .20x = .16(30)