Question 1199734
a) The initial height at t=0 is h(0) = 2.1
b) The maximum height occurs at the time where dh/dt = 0
dh/dt = 0 = -8.25/-14.6 = 0.565 s -> h = -7.3(0.565)^2 + 8.25(0.565) + 2.1 = 4.43 m
c) h(1) = 3.05 m