Question 1199667
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A = event of selecting a chocolate chip cookie on the 1st selection
P(A) = (number of chocolate chip)/(number total)
P(A) = (7 chocolate chip)/(7+6+8+5 total)
P(A) = (7 chocolate chip)/(26 total)
P(A) = 7/26


The fact that Jon eats the 1st cookie means no replacement is done.
This will affect the probability of the 2nd cookie (hence the events aren't independent).


B = event of selecting a sugar cookie on the 2nd selection


P(B given A) = probability B happens if event A happened
P(B given A) = (number of sugar cookies)/(total number left)
P(B given A) = (8 sugar cookies)/(26-1 left over)
P(B given A) = (8 sugar cookies)/(25 left over)
P(B given A) = 8/25
For more information, search out "conditional probability".


Lastly,
P(A and B) = P(A) * P(B given A)
P(A and B) = (7/26)*(8/25)
P(A and B) = 0.08615384615384 approximately
P(A and B) = 0.0862
There's about an 8.62% chance of this happening.


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Answer: <font color=red size=4>0.0862</font>
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