Question 1199654
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An investor invested a total of ​$800 in two mutual funds. 
One fund earned a 7​% profit while the other earned a 2% profit. 
If the​ investor's total profit was ​$26​, how much was invested in each mutual​ fund?
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Let x be the amount in dollars invested at 7%;
then the amount invested at 2% is the reat 800-x dollars.


Write the total annual interest equation

    0.07x + 0.02*(800-x) = 26  dollars.


Simplify it and find x

    0.07x + 16 - 0.02x = 26

    0.07x - 0.02x = 26 - 16

         0.05x    =    16

             x    =    16/0.05 = 1600/5 = 320.


<U>ANSWER</U>.  $320 invested at 7%, the rest, or $800 - $320 = $480 invested at 2%.


<U>CHECK</U>.  0.07*320 + 0.02*480 = 32 dollars, the total annual interest.   ! correct !
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Solved.