Question 1199630
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x^2 + y^2 ≤ 36
x^2 + (-4)^2 ≤ 36
x^2 + 16 ≤ 36
x^2 ≤ 36-16
x^2 ≤ 20
sqrt(x^2) ≤ sqrt(20)
|x| ≤ sqrt(20)
|x| ≤ 4.4721 approximately
-4.4721 ≤ x ≤ 4.4721  
-4 ≤ x ≤ 4 when x is an integer


The x coordinates span from -4 to 4, including both endpoints.
The x value is from the set {-4, -3, -2, -1, 0, 1, 2, 3, 4}


This constitutes 2*4+1 = 9 values of x, and hence there are 9 ordered pair integer solutions.
<table cellpadding = "9"><tr><td><font color=blue>(-4,-4)</font></td><td><font color=blue>(-3,-4)</font></td><td><font color=blue>(-2,-4)</font></td></tr><tr><td><font color=blue>(-1,-4)</font></td><td><font color=blue>(0,-4)</font></td><td><font color=blue>(1,-4)</font></td></tr><tr><td><font color=blue>(2,-4)</font></td><td><font color=blue>(3,-4)</font></td><td><font color=blue>(4,-4)</font></td></tr></table>Each pair has the y coordinate fixed to -4.


Unfortunately 9 isn't listed as a possible answer. Your teacher may have made a typo.


If I had to take a guess, it's possible your teacher wanted x to be nonzero. 
If so then we'd ignore the solution (0,-4) and we'd go from 9 solutions to 9-1 = 8 solutions. 
Again this is a guess of what your teacher wants. Ideally s/he should state all instructions and restrictions clearly.
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