<PRE><B>Question 1199590</B>
&lt;br&gt;
A has more coins than C; B has fewer than A; and C has half as many as B.  Since the number in C is smallest....&lt;br&gt;
Let x = # of coins in C
Then 2x = # of coins in B
And 5x = # of coins in A&lt;br&gt;
The number of coins in B is 12 less than the number in A:&lt;br&gt;
2x = 5x-12
3x = 12
x = 4&lt;br&gt;
The number of coins in A is 5x = 5*4 = 20.&lt;br&gt;
ANSWER: 20*($1) = $20&lt;br&gt;
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