Question 1199574
null hypothesis is .5 females and .5 males.
sample size is 14
standard error is equal to (.5  * .5 / 14) ^ .5 = .1336.
critical z-score at .05 alpha on the high end is equal to 1.645.
test z-score is (4/14 - .5) / .1336 = -1.6039
area to the right of that z-score is equal to .9456.
this is well abobve the critical alpha os .05, therfore the conclusion is that the hormones do not increasde the number of females in the population.


in fact, it appears that the hormones decrease the number of females in the population.


null hypothesis is .5 females and .5 males.
sample size is 14.
standard error i equal to (.5 * .5 / 14) ^ .5 = .1336.
test z-score is (4/14 - .5) / .1336 = -1.6039.
area to the left of that z-score is equal to .054.
this is slightly greater than the critical alpha of .05, therefore the conclusion is that the hormones do not decrease the number of females in the population, although the results are much closer to being significant than the test that the hormones increase the number of females in the population.