Question 1199559
sample size = 19
standard error = (.5 * .5 / 19) ^ .5 = .1147
critical z-score with one tailed .05 alpha on the high end is equal to 1.645.
sample z-score = (17/19 - .5) ./ .1147 = 3.44
this is well above the critical z-score, therefore the results are significant.