Question 1199552
Find the area of the parallelogram with the following vertices:


11. A(-2,3), B(5,8), C(3,3), and D(0,8)
<pre>
 A   D   B   C   A
-2   0   5   3  -2
 3   8   8   3   3
</pre>
Add the diagonal products starting upper left
-2*8 + 0*8 + 5*3 + 3*3 = -16+15+9 = 8
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Add the diagonal products starting lower left
3*0 + 8*5 + 8*3 + 3*-2 = 0+40+24-6 = 58
The difference is 50.
The area is 1/2 that, = 25 sq units.
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This works for all convex polygons, but the points have to be in order around the perimeter.  Notice it's A, D, B, C
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12. A(-2,7), B(-4,4), C(-11,4), and D(-9,7)

A. 15 sq units
B. 63 sq units
C. 28 sq units
D. 21 sq units
E. 36 sq units
F. 14 sq units