Question 1199504
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Informally, using logical reasoning and mental arithmetic....<br>
Since 1 adult ticket and 6 student tickets cost $60, 6 adult tickets and 36 student tickets would cost $360.
Comparing that to  the $192 cost of 6 adult tickets and 15 student tickets, we see that the 36-15=21 additional student tickets cost an additional $360-$192 = $168; so the cost of each student ticket is $168/21 = $8.
So on the first day the 6 student tickets cost 6($8) = $48, which means the 1 adult ticket cost $60-$48 = $12.<br>
ANSWER: The price of an adult ticket was $12.<br>
The exact same thing, using formal algebra....<br><pre>
x+6y = 60       given
6x+36y = 360    multiply by 6
6x+15y = 192    given
21y = 168       the difference between the two equations
y = 8           solve for y
x+6(8) = 60     solve for x
x+48 = 60
x = 12<br></pre>