Question 114572
FIRST YOU NEED TO FIND THE SLOPE OF THE GIVEN LINE.
Y=mX+b WHERE (m)=SLOPE.
2X-3Y=-7
-3Y=-2X-7
Y=-2X/-3-7/-3
Y=2X/3+7/3 THUS THIS SLOPE=2/3.
A PERPENDICULAR LINE WOULD HAVE A SLOPE = TO THE NEGATIVE RECIPRICAL OF THIS SLOPE.
THUS THE REQUIRED SLOPE=-3/2 FOR THE PERPENDICULAR LINE.
USING THE LINE FORMULA Y=mX+b & SUBSTITUTING THE POINT (6,-2) & THE SLOPE=-3/2 YOU NEED TO SOLVE FOR b THE Y INTERCEPT.
-2=-3/2*6+b
-2=-18/2+b
b=-2+9
b=7
SO THE LINE EQUATION IS:
Y=-3X/2+7